3k^2-24k+48=0

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Solution for 3k^2-24k+48=0 equation: 



3k^2-24k+48=0

a = 3; b = -24; c = +48;
Δ = b2-4ac
Δ = -242-4·3·48
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{24}{6}=4$

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